If a series circuit has two 13 kΩ resistors with a source voltage of 10 V, the wattage is:

To determine the wattage in a series circuit with two 13 kΩ resistors and a source voltage of 10 V, we first need to calculate the total resistance. In a series circuit, the total resistance is simply the sum of the individual resistances. Therefore, the total resistance is:

Total Resistance = R1 + R2 = 13 kΩ + 13 kΩ = 26 kΩ.

Next, we use Ohm’s Law to find the total current (I) in the circuit. Ohm’s Law states that ( V = I \times R ), or rearranged, ( I = \frac{V}{R} ). Thus, we have:

( I = \frac{10 V}{26,000 Ω} \approx 0.0003846 A ) or 384.6 µA.

Now, to find the power (wattage), we can use the formula for electrical power:

Power (P) = Voltage (V) × Current (I).

However, it can also be expressed in terms of resistance:

Using ( P = I^2 \times R ), we can substitute ( I ) and ( R ). The entire circuit uses the voltage drop